j^2+j-12=

Solution for j^2+j-12= equation:

Simplifying
j2 + j + -12 = 0

Reorder the terms:
-12 + j + j2 = 0

Solving
-12 + j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-4 + -1j)(3 + -1j) = 0

Subproblem 1
Set the factor '(-4 + -1j)' equal to zero and attempt to solve:

Simplifying
-4 + -1j = 0

Solving
-4 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1j = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1j = 0 + 4
-1j = 0 + 4

Combine like terms: 0 + 4 = 4
-1j = 4

Divide each side by '-1'.
j = -4

Simplifying
j = -4
Subproblem 2
Set the factor '(3 + -1j)' equal to zero and attempt to solve:

Simplifying
3 + -1j = 0

Solving
3 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1j = 0 + -3
-1j = 0 + -3

Combine like terms: 0 + -3 = -3
-1j = -3

Divide each side by '-1'.
j = 3

Simplifying
j = 3
Solution
j = {-4, 3}